-4.9x^2+27x+3=0

Solution for -4.9x^2+27x+3=0 equation:

-4.9x^2+27x+3=0

a = -4.9; b = 27; c = +3;
Δ = b2-4ac
Δ = 272-4·(-4.9)·3
Δ = 787.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-\sqrt{787.8}}{2*-4.9}=\frac{-27-\sqrt{787.8}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+\sqrt{787.8}}{2*-4.9}=\frac{-27+\sqrt{787.8}}{-9.8}
$